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fix: ignore virtual fields in filter UI (#34224)

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Raffael Meyer 2025-10-01 12:56:13 +02:00 • committed by GitHub
parent 55328049c5
commit 29e2e0cf86
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1 changed files with 5 additions and 1 deletions
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6
frappe/public/js/frappe/ui/filters/field_select.js
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@ -117,6 +117,10 @@ frappe.ui.FieldSelect = class FieldSelect {
// main table
var main_table_fields = std_filters.concat(frappe.meta.docfield_list[me.doctype]);
$.each(frappe.utils.sort(main_table_fields, "label", "string"), function (i, df) {
if (df.is_virtual) {
return;
}
let doctype =
frappe.get_meta(me.doctype).istable && me.parent_doctype
? me.parent_doctype
@ -128,7 +132,7 @@ frappe.ui.FieldSelect = class FieldSelect {
// child tables
$.each(me.table_fields, function (i, table_df) {
if (table_df.options) {
if (table_df.options && !table_df.is_virtual) {
let child_table_fields = [].concat(frappe.meta.docfield_list[table_df.options]);
if (table_df.fieldtype === "Table MultiSelect") {