3446026555
The license.txt file has been replaced with LICENSE for quite a while now. INAL but it didn't seem accurate to say "hey, checkout license.txt although there's no such file". Apart from this, there were inconsistencies in the headers altogether...this change brings consistency.
84 lines
2 KiB
Python
84 lines
2 KiB
Python
# Copyright (c) 2015, Frappe Technologies Pvt. Ltd. and Contributors
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# License: MIT. See LICENSE
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import frappe
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def get_parent_doc(doc):
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"""Returns document of `reference_doctype`, `reference_doctype`"""
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if not hasattr(doc, "parent_doc"):
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if doc.reference_doctype and doc.reference_name:
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doc.parent_doc = frappe.get_doc(doc.reference_doctype, doc.reference_name)
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else:
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doc.parent_doc = None
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return doc.parent_doc
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def set_timeline_doc(doc):
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"""Set timeline_doctype and timeline_name"""
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parent_doc = get_parent_doc(doc)
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if (doc.timeline_doctype and doc.timeline_name) or not parent_doc:
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return
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timeline_field = parent_doc.meta.timeline_field
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if not timeline_field:
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return
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doctype = parent_doc.meta.get_link_doctype(timeline_field)
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name = parent_doc.get(timeline_field)
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if doctype and name:
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doc.timeline_doctype = doctype
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doc.timeline_name = name
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else:
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return
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def find(list_of_dict, match_function):
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'''Returns a dict in a list of dicts on matching the conditions
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provided in match function
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Usage:
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list_of_dict = [{'name': 'Suraj'}, {'name': 'Aditya'}]
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required_dict = find(list_of_dict, lambda d: d['name'] == 'Aditya')
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'''
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for entry in list_of_dict:
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if match_function(entry):
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return entry
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return None
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def find_all(list_of_dict, match_function):
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'''Returns all matching dicts in a list of dicts.
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Uses matching function to filter out the dicts
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Usage:
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colored_shapes = [
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{'color': 'red', 'shape': 'square'},
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{'color': 'red', 'shape': 'circle'},
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{'color': 'blue', 'shape': 'triangle'}
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]
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red_shapes = find_all(colored_shapes, lambda d: d['color'] == 'red')
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'''
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found = []
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for entry in list_of_dict:
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if match_function(entry):
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found.append(entry)
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return found
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def ljust_list(_list, length, fill_word=None):
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"""
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Similar to ljust but for list.
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Usage:
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$ ljust_list([1, 2, 3], 5)
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> [1, 2, 3, None, None]
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"""
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# make a copy to avoid mutation of passed list
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_list = list(_list)
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fill_length = length - len(_list)
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if fill_length > 0:
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_list.extend([fill_word] * fill_length)
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return _list
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